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When two waves meet at a point, their equations are,\mathrm{y_1=2 a \cos \omega t }

                                                                             \mathrm{ y_2=3 a \cos \left(\omega t+\frac{\pi}{2}\right) .}

The amplitude of a resultant wave is-
 

Option: 1

\mathrm{a}

 


Option: 2

\mathrm{5 a}
 


Option: 3

\mathrm{3.6 a}
 


Option: 4

\mathrm{2.23 a}


Answers (1)

best_answer

phase difference between two equations is \mathrm{\pi / 2 }

Hence,\mathrm{ a_R=\sqrt{9 a^2+4 a^2} }

          \mathrm{ a_R=\sqrt{13 a} }

          \mathrm{ a_R=3.6 a}

Hence option 3 is correct.




 

Posted by

manish

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