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When ultraviolet light of wavelength 100\mathrm{~nm} is incident upon silver plate, a potential of 7.7 \mathrm{~V}is required to stop the photoelectrons from reaching the collector plate. How much potential will be required to stop the photoelectrons when light of wavelength 200\mathrm{~nm} is incident upon silver?

Option: 1

1.5 \mathrm{~V}


Option: 2

3.85\mathrm{~V}


Option: 3

2.35\mathrm{~V}


Option: 4

15.4 \mathrm{~V}


Answers (1)

best_answer

\begin{aligned} & \lambda_1=\frac{12375}{E_1(e V)} \AA=1000 \AA \\ & \therefore \quad E_1=12.375 \mathrm{eV} \\ & \text { Similarly, } E_2=\frac{12375}{\lambda_2(\AA)} e V=\frac{12375}{2000}=6.1875 \mathrm{eV} \\ & \text { Now, } E_1-W_0=eV_s \\ & \text { and } E_2-W_0=eV_s \\ & \text { Hence, } 12.375-W_0=7.7 eV_s \\ & \text { and } 6.1875-W_0=eV_s \\ & \text { Solving, we get } V_s=1.5 V \end{aligned}

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himanshu.meshram

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