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Which of the following is the correct graph for a second order reaction?
Here,
$\mathrm{t}_{1 / 2}$ is the half-life period.
$\mathrm{{(Concentration)}_{i}}$ is the initial concentration of the reactant.
Option: 1

Option: 2

Option: 3

Option: 4

Answers (1)

best_answer

For a second order reaction:
$\mathrm{ \frac{1}{[A]}=k t+\frac{1}{[A]_0} }$
$\mathrm{ [A]_0 }$ is the initial concentration.
$\mathrm{ [A] }$ is the concentration at time t.

$\mathrm{ \text { At } t=t_{\frac{1}{2}},[A]=\frac{A_0}{2} }$

Putting the values
$\mathrm{ \frac{2}{[A]_0}=k t_{\frac{1}{2}}+\frac{1}{[A]_0} \\ }$

$\mathrm{ t_{\frac{1}{2}}=\frac{1}{[A]_0 k} }$

Graph between $\mathrm{ t_{\frac{1}{2}} }$ and $\mathrm{ \frac{1}{[A]_0} }$ is a straight line with slope of $\mathrm{ \frac{1}{k} }$

Second order:

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Riya

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