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Which of the following physical quantities have the same dimensions?
 

Option: 1

Electric displacement (\overrightarrow{\mathrm{D}}) and surface charge density
 


Option: 2

Displacement current and electric field
 


Option: 3

Current density and surface charge density
 


Option: 4

Electric potential and energy


Answers (1)

best_answer

\mathrm{[Electric \: \: displacement ]=[D]=\left[\frac{\text { charge }}{\text { area }}\right]}

                                                         \mathrm{=\left[A^{\prime} T^{\prime} L^{-2}\right]}

\mathrm{\left[\begin{array}{c}\text { Surface charge } \\ \text { density }\end{array}\right]=\left[\frac{Q}{A}\right]=\left[A^{\prime} T^{\prime} L^{-2}\right]}

\mathrm{[Current \: density ]=[J]=\left[\frac{I}{A}\right]=\left[A^{\prime} L^{-2}\right]}

\mathrm{[Electric \: field ]=\left[M^{\prime} L^1 T^{-3} A^{-1}\right]}

Hence (1) is correct option.

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Nehul

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