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Which of the following statement is correct regarding the AC circuit shown in the adjacent figure?
                                                    

Option: 1

The rms value of current through the circuit is \mathrm{i}_{\mathrm{rms}}=5 \sqrt{2} \mathrm{~A}


Option: 2

The phase difference between source emf and current is \phi=\cos ^{-1}\left(\frac{1}{3}\right)


Option: 3

Average power dissipated in the circuit is 500 W


Option: 4

None of the above


Answers (1)

best_answer

\mathrm{\begin{aligned} & \mathrm{X}_{\mathrm{C}}=\mathrm{X}_{\mathrm{L}} \\ & \therefore \mathrm{Z}=\mathrm{R}=2 \Omega \Rightarrow \mathrm{I}_{\mathrm{rms}}=\frac{\mathrm{V}_{\mathrm{mms}}}{\mathrm{Z}}=\frac{100 / \sqrt{2}}{2}=25 \sqrt{2} \mathrm{~A} \end{aligned} }
Phase difference will be zero.
\mathrm{\text { Average power }=\mathrm{V}_{\mathrm{rms}} \mathrm{I}_{\mathrm{mms}} \cos \phi=\frac{100}{\sqrt{2}} \times 25 \sqrt{2} \times \cos 0^{\circ}=2500 \mathrm{~W}}

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avinash.dongre

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