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The major product of the following reaction is

• Option 1)

• Option 2)

• Option 3)

• Option 4)

Side chain chlorination followed by hydrolysis - The halogenation/chlorination of Toluene can occur in 2 methods of electrophilic substitution: The Chlorine either substitutes itself with a Hydrogen atom in the phenyl ring, or it substitutes with a Hydrogen atom in the Methyl group (side chain reaction) to form variants of Chloromethylbenzene/Benzyl Chloride (C6H5CH2Cl).   Electrophilic...

Moment of inertia of a body about a given axis is $1.5\:kg\:m^{2}$. Initially the body is ate rest. In order to produce a rotational kinetic energy of $1200\:J$ , the angular acceleration of $20\:rad/s^{2}$ must be applied about the axis for a duration of :

• Option 1)

$2.5\:s$

• Option 2)

$2\:s$

• Option 3)

$5\:s$

• Option 4)

$3\:s$

Given      Option 1)Option 2)Option 3)Option 4)

In a conductor , if the number of conduction electron per unit volume is $8.5\times 10^{28}m^{-3}$  and mean free time is $25\:fs$ ( femto second ) , it's approximate resistivity is :

$(m_{e}=9.1\times10^{-31}kg)$

• Option 1)

$10^{-6}\:\:\Omega\:m$

• Option 2)

$10^{-7}\:\:\Omega\:m$

• Option 3)

$10^{-8}\:\:\Omega\:m$

• Option 4)

$10^{-5}\:\:\Omega\:m$

Resistivity - - wherein It is independent of shape and size of the body i.e.  and      we know that , Option 1) Option 2) Option 3) Option 4)

The major product in the following reaction is:

• Option 1)

• Option 2)

• Option 3)

• Option 4)

Basicity of Aromatic Amines - The unshared pair of electrons at the nitrogen atom is in resonance with the benzene ring and hence not fully available for donation as in the case of aniline. -       Nature of group and basicity - Electron withdrawing groups ( -I and -M  effect ) decreases basicity, whereas Electron releasing groups ( +I and +M  effect ) increases basicity. -...

Diborane $(B_{2}H_{6})$ reacts independenttly with $O_{2}$  and $H_{2}O$ to produce, respectively:

• Option 1)

$H_{3}BO_{3}\; and\; B_{2}O_{3}$

• Option 2)

$B_{2}O_{3}\; and\; [BH_{4}]^{-}$

• Option 3)

$B_{2}O_{3}\; and\;H_{3}BO_{3}$

• Option 4)

$HBO_{2}\; and\;H_{3}BO_{3}$

Diborane - Simplest boron hydride, dimer of BH3, colourless and highly toxic gas - wherein Hybridisation of boron in diborane is sp3       Preparation of diborane in laboratory - By the oxidation of sodium borohydride with I2 - wherein       Preparation of diborane from boron halides - -       Oxides of boron family - Acidity decreases and basicity increases down the group General...

Which of the following statements is not true about sucrose ?

• Option 1)

It is a non reducing sugar

• Option 2)

The glycosidic linkage is present between $C_{1}$ of $\alpha -glucose$ and $C_{1}$ of $\beta -fructose$

• Option 3)

It is also named as invert sugar

• Option 4)

On hydrolysis, it produces glucose and fructose

a) Sucrose is non - reducing sugar b)              . C)  It is invert sugar d) Sucrose  So option (b) is incorrect     it has    Option 1)It is a non reducing sugarOption 2)The glycosidic linkage is present between  of  and  of Option 3)It is also named as invert sugarOption 4)On hydrolysis, it produces glucose and fructose

The compound that inhibits the growth of tumors is:

• Option 1)

$trans-\left [ Pt\left ( Cl \right )_{2} \left ( NH_{3} \right )_{2} \right ]$

• Option 2)

$cis-\left [ Pd\left ( Cl \right )_{2} \left ( NH_{3} \right )_{2} \right ]$

• Option 3)

$cis-\left [ Pt\left ( Cl \right )_{2} \left ( NH_{3} \right )_{2} \right ]$

• Option 4)

$trans-\left [ Pd\left ( Cl \right )_{2} \left ( NH_{3} \right )_{2} \right ]$

Application of coordination compounds - Coordination compounds are used for many applications: Extraction process of gold and silver. Used as catalyst in many industrial processes. Purification of metals. Hardness of water.(EDTA) EDTA is used in treatment of lead poisoning. Chelate therapy (removal of toxic proportion of metals in the body) Platinum compounds inhibit the growth...

Magnesium powder burns in air to give :

• Option 1)

$Mg(NO_{3})_{2}\; and\; Mg_{3}N_{2}$

• Option 2)

$MgO \; and\; Mg_{3}N_{2}$

• Option 3)

$MgO\; only$

• Option 4)

$MgO\; and \; Mg(NO_{3})2$

Reactivity of alkaline earth metals with O2 - Increases down the group - wherein Due to increase in elecropositive character     Option 1)          Option 2)Option 3)Option 4)

The major product of the following reaction is :

$CH_{3}C\equiv CH\xrightarrow[(ii)\; DI]{(i)\; DCl\left ( 1\; equiv. \right )}$

• Option 1)

$CH_{3}CD(I)CHD(Cl)$

• Option 2)

$CH_{3}CD(Cl)CHD(I)$

• Option 3)

$CH_{3}CD_{2}CH(Cl)(I)$

• Option 4)

$CH_{3}C(I)(Cl)CHD_{_{2}}$

Markovnikov's Rule - Negative part of the reagent attacks on that carbon of multiple bond which have less number of   hydrogen atoms. - wherein     Addition of Hydrogen halide on alkyne - Reaction takes place according to Markovnikov's rule. - wherein                          Markonikov rule                                               Option 1)                 Option 2)Option 3)Option 4)

0.27 g of a long chain fatty acid was dissolved in 100 cm3 of hexane. 10 mL of this solution was added dropwise to the surface of water in a round watch glass. Hexane evaporates and a monolayer is formed. The distance from edge to centre of the watch glass is 10 cm. What is the height of the monolayer?

[Density of fatty acid=0.9 g cm-3 , $\pi=3$]

• Option 1)

10-6 m

• Option 2)

10-8 m

• Option 3)

10-2 m

• Option 4)

10-4 m

Density - Density is a measure of mass per unit  volume. The average density of an object is equals to its total mass divided by its total volume. An object made from a comparatively dense material (such as iron) will have less volume than an object of equal mass made from some less dense substance (such as water). To find the density of any object, we need to know the Mass (grams) of the...

The major product obtained in the following reaction is:

• Option 1)

• Option 2)

• Option 3)

• Option 4)

Aldol condensation - Aldehydes and ketones possessing  - hydrogen atom in the presence of dilute alkali undergo self-condensation to form   - hydroxy aldehyde and    - hydroxy ketone. - wherein                  Product  (1) It is aldol conchensation Mechanism is as follows Note:- there in 1 step there will be formation of evolate  Option 1)Option 2)Option 3)Option 4)

The major product of the following reaction is :

$CH_{3}CH=CHCO_{2}CH_{3}\xrightarrow{LiAlH_{4}}$

• Option 1)

$CH_{3}CH_{2}CH_{2}CO_{2}CH_{3}$

• Option 2)

$CH_{3}CH=CHCH_{2}OH$

• Option 3)

$CH_{3}CH_{2}CH_{2}CH_{2}OH$

• Option 4)

$CH_{3}CH_{2}CH_{2}CHO$

Alcohol formation by reduction of esters - Yields two alcohols - wherein      do not reduce alkeneOption 1)           Option 2)Option 3)Option 4)

A message signal of frequency 100 MHz and peak voltage 100V is used to execute amplitude

modulation on a carrier wave of frequency 300 GHz and peak voltage 400V. The modulation

index and difference between the two side band frequencies are:

• Option 1)

$4;1\times 10^{8}\: Hz$

• Option 2)

$4;2\times 10^{8}\: Hz$

• Option 3)

$0.25;2\times 10^{8}\: Hz$

• Option 4)

$0.25;1\times 10^{8}\: Hz$

Modulation Index - The ratio of change of amplitude of carrier wave to the amplitude of original carrier wave. - wherein     Side band frequency - AM wave contains three frequency   - wherein is carrier frequency, are side band frequency.     Band Width - The two side band lie on either side of the carrier frequency at equal frequency intravel, fm - wherein...

The major product of the following reaction is :

• Option 1)

• Option 2)

• Option 3)

• Option 4)

Alcohols reaction with hydrogen halides - Forms alkyl halides. - wherein     Alcohols reaction with hydrogen halides - Forms alkyl halides. - wherein       CN is strong electron withdrawing group, therefore it will create  charge on adjacent carbon and thus (  ) will attack on this carbon by  mechanism. Thus, NOTE: answer provided by NTA is wrong. The answer provided by us is...

The major product of the following reaction is :

• Option 1)

• Option 2)

• Option 3)

• Option 4)

Alcohols reaction with phosphorus trihalides - Form alkyl halides  - wherein X = Cl, Br, I     Option 1)   Option 2) Option 3)   Option 4)

A ball is thrown upward with an initial velocity $V_{o}$ from the surface of the earth.

The motion of the ball is affected by a drag force equal to $m\gamma v^{2}$ ( where m is

mass of the ball, v is its instataneous velocity and $\gamma$ is a constant). Time taken

by the ball to rise to its zenith is:

• Option 1)

$\frac{1}{\sqrt{\gamma g}}\tan^{-1}(\sqrt{\frac{\gamma }{g}}V_{o})$

• Option 2)

$\frac{1}{\sqrt{\gamma g}}\sin^{-1}(\sqrt{\frac{\gamma }{g}}V_{o})$

• Option 3)

$\frac{1}{\sqrt{\gamma g}}\ln(1+\sqrt{\frac{\gamma }{g}}V_{o})$

• Option 4)

$\frac{1}{\sqrt{2\gamma g}}\tan^{-1}(\sqrt{\frac{2\gamma }{g}}V_{o})$

Newton's 2nd Law -     Therefore   - wherein  in C.G.S & S.I Force can be defined as rate of change of momentum.     =>  =>  Option 1) Option 2) Option 3) Option 4)

But-2-ene on reaction with alkaline $KMnO_{4}$ at elevated temperature followed by acidification will give:

• Option 1)

$2$ molecules of $CH_{3}COOH$

• Option 2)

$2$ molecules of $CH_{3}CHO$

• Option 3)

one molecule of $CH_{3}CHO$ and one molecule of $CH_{3}COOH$

• Option 4)

Oxidation of alkene - Alkene on reaction with cold dilute aqueous solution of KMnO4 (Bayers Reagent) produce vicinal glycol. Decolourisation  of KMnO4 solution is used as a test of unsaturation. - wherein            ...

The electrons are more likely to be found:

• Option 1)

in the region a and c

• Option 2)

in the region a and b

• Option 3)

only in the region a

• Option 4)

only in the region c

The energy (E) of a quantum of radiation - Where h is plank’s constant and  is frequency -     Bohr's model - 1. Force of attraction between the nucleus and an electron is equal to centripetal force. 2.      n = principal quantum number. 3. Energy can be absorbed or emitted when electron transfer orbit   -   We knew that probability of finding an electron is proportional  Now on converting...

Which of the following is a thermosetting polymer?

• Option 1)

PVC

• Option 2)

Nylon 6

• Option 3)

Buna-N

• Option 4)

Bakelite

Thermosetting Polymers - They are highly cross - linked, hard, infusible and insoluble polymers.They cannot be reused. - wherein Eg:-  Bakellite, Urea,  Formaldehyde, Resin, etc       Bakelite is an example of the thermosetting polymer.  Bakelite is another name of Phenal formaldehyde. It is a thermosetting  polymer because it has cross linked structure. It can't be revised once it is...

The correct statement among the following is :

• Option 1)

$\left ( SiH_{3} \right )_{3}N$ is pyramidal and less basic than $\left (CH_{3} \right )_{3}N$.

• Option 2)

$\left ( SiH_{3} \right )_{3}N$nis planar and less basic than  $\left (CH_{3} \right )_{3}N$.

• Option 3)

$\left ( SiH_{3} \right )_{3}N$ is planar and more basic than $\left (CH_{3} \right )_{3}N$.

• Option 4)

$\left ( SiH_{3} \right )_{3}N$ is pyramidal and more basic than $\left (CH_{3} \right )_{3}N$.

Electronegativity of Nitrogen family - Gradually decreases down the group. More electronegative than group 14 -       Positive oxidation state of Nitrogen family - Shows +3 and +5 oxidation states (except N2) Stability of +3O.S increases down the group due to inert pair effect - wherein +3 when only p electron are involved and +5 when all valence five (s and p) electrons are...
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