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What is the molar solubility of Al\left ( OH \right )_{3} in 0.2M\: \: \: \: NaOH solution? Given that, solubility product of Al\left ( OH \right )_{3}=2.4\times 10^{-24}:

 

 

  • Option 1)

  • Option 2)

  • Option 3)

  • Option 4)

Solubility and K{H} values - Gases having more values will have less solubility. -         Option 1)Option 2)Option 3)Option 4)

1\; g of a non-volatile non-electrolyte solute is dissolved in 100 \; g of two different solvents A and B whose ebulliscopic constants are in the ratio of 1:5. The ratio of the elevation in their boiling points,\frac{\Delta T_{b}\left ( A \right )}{\Delta T_{b}\left ( B \right )}, is :

  • Option 1)

    5:1

  • Option 2)

    10:1

  • Option 3)

    1:5

  • Option 4)

     1:0.2

                                   given  ------------------------(1)                                                                                   -------------------------(2)                        Option 1)Option 2)Option 3)Option 4) 

Molal depression constant for a solvent is 4.0\:\:K\:kg\:mol^{-1}. The depression in the freezing point of the solvent for 0.03\:\:\:mol\:kg^{-1}\:\:solution\:\:of\:\:K_{2}SO_{4}  is :

( Assume complete dissociation of the electrolyte )

  • Option 1)

    0.18\:K

  • Option 2)

    0.24\:K

  • Option 3)

    0.12\:K

  • Option 4)

    0.36\:K

  Depression in freezing point - -     Mathematical Expression of Depression in Freezing point -   - wherein m = molarity of solvent  = cryoscopic  constant     molal depress const Units =     Vant Hoff factor (i) - In case of electrolytes the observed colligative property is different from theoritical colligative property. There ratio is defined by Vant Haff factor - wherein...

The osmotic pressure of a dilute solution of an ionic compound XY in water is four times that of a solution of 0.01 \; M BaCl_{2} in water. Assuming complete dissociation of the given ionic compounds in water, the concentration of XY\left ( in \; mol\; L\; ^{-1} \right ) in solution is :

  • Option 1)

     4\times 10^{-2}                

  • Option 2)

     6\times 10^{-2}

  • Option 3)

     4\times 10^{-4}

  • Option 4)

    16\times 10^{-4}

 
Given,        Option 1)                   Option 2)   Option 3)   Option 4)

Liquid 'M' and liquid 'N' form an ideal solution. The vapour pressures of pure liquids 'M' and 'N' are 450 and 700 \; mmHg, respectively, at the same temperature. Then correct statement is :

\left ( x_{M}=Mole\; fraction \; of\; 'M' \; in\; solution;

x_{N}=Mole\; fraction \; of\; 'N' \; in\; solution;

y_{M}=Mole\; fraction \; of\; 'M' \; in\; vapour\; phase;

y_{N}=Mole\; fraction \; of\; 'N' \; in\; vapour\; phase )

 

  • Option 1)

      \frac{x_{M}}{x_{N}}=\frac{y_{M}}{y_{N}}       

     

  • Option 2)

    \left ( x_{M}-y_{M} \right )< \left ( x_{N}-y_{N} \right )

  • Option 3)

      \frac{x_{M}}{x_{N}}< \frac{y_{M}}{y_{N}}

  • Option 4)

     \frac{x_{M}}{x_{N}}> \frac{y_{M}}{y_{N}}

 
More volatile component will have greater composition in vapour phase as compared to it's composition in liq.phase The vapour phase of pure liq.  &  are  of  and  of   respectively           ( more volatile) Option 1)             Option 2) Option 3)    Option 4)  

For the solution of the gases, w,x,y and z in water at 298 K, the henry's law constants (KH) are 0.5,2,35 and 40 kbar, respectively. The correct plot for the given data is 

  • Option 1)

  • Option 2)

  • Option 3)

  • Option 4)

                                                                                                                    Option 1)Option 2)Option 3)Option 4)

The vapour pressures of pure liquids A and B are 400 and 600 mmHg, respectively at 298 K. On mixing the two liquids, the sum of their initial volumes is equal to the volume of the final mixture.  The mole fraction of liquids B is 0.5 in the mixture. The vapour pressure of the final solution, the mole fractions of components A and B in vapour phase, respectively are :
 

  • Option 1)

    450\; mmHg,0.5,0.5

  • Option 2)

    450\; mmHg,0.4,0.6

  • Option 3)

    500\; mmHg,0.4,0.6

     

  • Option 4)

    500\; mmHg,0.5,0.5

                                                                      mole fraction of A in vapour phase Option 1)Option 2)Option 3)  Option 4)

The molar solubility of Cd(OH)_{2} is 1.84\times 10^{-5}M in water. The expected solubility of Cd(OH)_{2} in a buffer solution of pH = 12 is :

 

  • Option 1)

    1.84\times 10^{-9}M

     

     

     

  • Option 2)

    \frac{2.49}{1.84}\times 10^{-9}M

  • Option 3)

    6.23\times 10^{-11}M

  • Option 4)

    2.49\times 10^{-10}M

 of                                  S               2S+    2S - > this OH comes from dissociation of      - > this OH comes from a buffer                                        Given                            Option 1)      Option 2)Option 3)Option 4)

A solution is prepared by dissolving 0.6 g of urea (molar mass =60g mol^{-1} ) and 1.8 g of glucose (molar mass = 180 g mol^{-1} ) in 100 mL of water at 27^{\circ}C. The osmotic pressure of the solution is:

(R=0.08206 L atm K^{-1}mol^{-1})

  • Option 1)

    8.2 atm

  • Option 2)

    2.46 atm

  • Option 3)

    4.92 atm

  • Option 4)

    1.64 atm

molar of Urea                                                      Given Water = 100ml molar of glucose =                                                   Temp = 300 k Total moles =  Osmotic pressure =  Option 1)8.2 atmOption 2)2.46 atmOption 3)4.92 atmOption 4)1.64 atm

The freezing point of a diluted milk sample is found to be -0.2^{0}C , while it should have been -0.5^{0}C for pure milk. How much water has been added  to pure milk  to make the diluted sample ?

  • Option 1)

    2 cups of water to 3 cups of pure milk.

  • Option 2)

    3 cups of water to 2 cups of pure milk.

  • Option 3)

    1 cup of water to 3 cups of pure milk.

  • Option 4)

    1 cup of water to 2 cups of pure milk.

  Depression in freezing point - -       Freezing -  Freezing  occurs when liquid solvent is in equilibrium with solid solvent. As non volatile solute decreases, the vapour pressure freezing point decreases. -As we knoew that Freezing point of milk Freezing point of milk (diluted)      Option 1)2 cups of water to 3 cups of pure milk.Option 2)3 cups of water to 2 cups of pure milk.Option 3)1...

Among the colloids cheese (C), milk (M) and smoke (S), the correct combination of the dispersed phase and dispersion medium, respectively is :

  • Option 1)

    C : liquid in solid ; M : Liquid in Solid ; S solid in gas 

  • Option 2)

    C : liquid in solid ; M : Liquid in liquid ; S : solid in gas 

  • Option 3)

    C : solid in liquid  ; M : Liquid in Liquid ; S : solid in gas 

  • Option 4)

    C : solid in liquid  ; M : Solid in liquid; S : solid in gas 

  Types of solutions - a)    Liquid solute and Liquid solvent b)    Solid solute and Liquid solvent c)    Gaseous solute and Liquid solvent d)    Solid solute and Solid solvent e)    Liquid solute and Solid solvent f )    Gaseous solute and Solid solvent g)    Solid solute and Gaseous solvent h)    Liquid solute and Gaseous solvent i)     Gaseous solute and Gaseous solvent -       Solutions - A...

K_{2}HgI_{4} is 40 % ionised in aqueous solution. 

The value of its van't Hoff factor (i) is :

  • Option 1)

    2.2

  • Option 2)

    1.8

  • Option 3)

    2.0

  • Option 4)

    1.6

  Vant Hoff factor (i) - In case of electrolytes the observed colligative property is different from theoritical colligative property. There ratio is defined by Vant Haff factor - wherein       Vant Hoff factor for dissociation - Where is the no. of dissociated particles degree of dissociation   - wherein       Vant Hoff factor for Association - number of particles associated ...

If K_{sp} of Ag_{2}CO_{3} is 8 \times 10^{-12}, the molar solubility of Ag_{2}CO_{3} in 0.1 M AgNO_{3} is :

  • Option 1)

    8 \times 10^{-11} M

     

  • Option 2)

    8 \times 10^{-12}

  • Option 3)

    8 \times 10^{-10}

  • Option 4)

    8 \times 10^{-13} M

  Relation between concentration terms (Molality & Mole fraction) - - wherein         Relation between concentration terms (Molality & Molarity) - - wherein As we have learned in solution The reaction is      Option 1) M  Option 2) M Option 3) M Option 4) M

Elevation in the boiling point for 1 molal solution og glucose is 2 K .the depression inthe freezing point for 2molal solution of glucose in the same solvent is 2  ,K.the relatin between Kb and Kfis:

  • Option 1)

    Kb = Kf

  • Option 2)

    Kb =1.5 Kf

  • Option 3)

    Kb =0.5 Kf

  • Option 4)

    Kb =2 Kf

  Mathematical Expression - Unis of   - wherein     Mathematical Expression of Depression in Freezing point -   - wherein m = molarity of solvent  = cryoscopic  constant     molal depress const Units =   As we have learned The change in Tb and Tf . Option 1)Kb = KfOption 2)Kb =1.5 KfOption 3)Kb =0.5 KfOption 4)Kb =2 Kf

A mixture of 100 m mol of Ca(OH)_{2} and 2 g of sodium sulphate was dissolved in water and the volume was made up to 100 mL .The mass of calcium sulphate formed and the concentration of OH^{-} in resulting solution , respectively , are  : (Molar mass of  Ca(OH)_{2}  ,Na_{2}SO_{4} \: and \: \: CaSO_{4} are 74, 143 and 136 g mol^{-1} , respectively ; K_{sp} \: \: of\: \: Ca(OH)_{2}\: \: is\: \: 5.5\times 10^{-6})

  • Option 1)

    1.9\: g,\: \: 0.28\: mol\: L^{-1}

  • Option 2)

    13.6g,\: \: 0.28\: molL^{-1}

  • Option 3)

    1.9g,\: \: 0.14molL^{-1}

  • Option 4)

    13.6g,\: \: 0.14molL^{-1}

@    Mole Fraction - - As we have learned in mole concept . The reaction is -       Vapour Pressure - It is defined as pressure exerted by vapours on liquid surface at equilibrium and condensation. -        Raoult's Law - The partial pressure of any volatile constituents of a solution at a given temperature is equal to the product of vapour pressure of pure constituent and its mole fraction...

Liquids A and B form an ideal solution in the entire composition range . At 350 K , the vapor pressures of pure A and pure B are7\times 10^{3}Pa\: \: and\: \: 12\times 10^{3}Pa , respectively . The composition of the vapor in equilibrium with a solution containing 40 mol percent of A at this temperature is :

  • Option 1)

    x_{A}=0.37; \: x_{B}=0.63

  • Option 2)

    x_{A}=0.28; \: x_{B}=0.72

  • Option 3)

    x_{A}=0.4; \: x_{B}=0.6

  • Option 4)

    x_{A}=0.76; \: x_{B}=0.24

  Mole Fraction - -     Vapour Pressure - It is defined as pressure exerted by vapours on liquid surface at equilibrium and condensation. -       Negative deviation from Raoult's Law behaviour - When the pressure exerted by vapours of mixture is less than that in case of ideal behaviour. - wherein       Factors affecting vapour pressure - - wherein It depends only on temperature and nature...

A solution containg 62 g ethylene glycol in 250 g water is cooled to -10^{0}C . If K_{f} for water is 1.86  K kg mol^{-1}, the amount of water (in g ) separated as ice  is:

  • Option 1)

    16

  • Option 2)

    32

  • Option 3)

    48

  • Option 4)

    64

  Dependence of K_{f} - -     Solutions - A homogeneous mixture of solute and solvent present in same phase. - wherein Eg. Nacl in H2O     Definition of Boiling - Boiling occurs at the temperature when the vapour pressure of liquid becomes equal to external atmospheric pressure - wherein Boiling point of pure liquid is fixed. The formula :    Option 1)16Option 2)32Option 3)48Option 4)64

Which one of the following statement regarding Henry's law is not corret?

  • Option 1)

    Higher the value of K_{H} at a given pressure , higher is the solubility of the gas in the liquids.

  • Option 2)

    Different gases have different K_{H} (Henry's law constant) value at the same tempreture

  • Option 3)

    The partial pressure of the gas in vapour phase is prootional to the mole fraction of the gas in the  solution

  • Option 4)

    The value of K_{H} incerases with increase of temperature and K_{H}is function of the nature of the gas

  Henry's Law - It decides the solubility of gases in liquids. = mole fraction of gas in liquid. = Partial pressure of gas over liquid surface. -as we know that , (liquid solution) more is KH then less will be solublity,lesser the solublity is at higher temperture so more is temperture more will be KH    Option 1)Higher the value of at a given pressure , higher is the solubility of the gas...
Engineering
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 For an ideal solution of two components A and B, which of the following is true ?

  • Option 1)

     \DeltaHmixing < 0 (zero)              
     

  • Option 2)

    \DeltaHmixing > 0 (zero)            
                 

  • Option 3)

     A-B interaction is stronger than      
        A-A and B-B interactions       
     

  • Option 4)

    A-A, B-B and A-B interactions      
        are identical            

 
As we have learnt,   Condition of ideality - Interaction between A - A; B - B are similar to A - B Interactions. eg. Hexane + Heptone Benzene + Toluere - wherein       Fact. Option 1)  Hmixing < 0 (zero)                 Option 2) Hmixing > 0 (zero)                           Option 3)  A-B interaction is stronger than           A-A and B-B interactions          Option 4) A-A, B-B and...
Engineering
102 Views   |  

Osmotic pressure of a solution containing 0.1 mole of solute per litre at 273K is (in atm)

  • Option 1)

    \frac{0.1}{1}\times 0.08205\times 273

     

     

     

  • Option 2)

    0.1\times 1\times 0.08205\times 273

  • Option 3)

    \frac{1}{0.1}\times 0.08205\times 273

  • Option 4)

    \frac{0.1}{1}\times \frac{273}{0.08205}

 
As we learned    Mathematical Expression for Osmotic Pressure -   - wherein Representation of osmotic pressure.       Option 1)       Option 2) Option 3) Option 4)
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