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Engineering
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Three thermochemical equations are given below

(i) $C_{\left ( graphite \right )}+O_{2}\left ( g \right )\rightarrow CO_{2}\left ( g \right );$

$\Delta _{r} H^{o}=xkJmol^{-1}$

(ii) $C_{\left ( graphite \right )}+\frac{1}{2}O_{2}\left ( g \right )\rightarrow CO\left ( g \right );$

$\Delta _{r} H^{o}=ykJmol^{-1}$

(iii) $CO\left ( g \right )\frac{1}{2}O_{2}\left ( g \right )\rightarrow CO_{2}\left ( g \right );$

$\Delta _{r} H^{o}=zkJmol^{-1}$

Based on the above equations, find out which of the relationship given below is correct?

• Option 1)

x=y-z

• Option 2)

z=x+y

• Option 3)

x=y+z

• Option 4)

y=2z-x

As we learnt in Hess's Law - The total amount of heat change in a chemical reaction is the same whether the reaction is carried  out in one or several steps by one or more methods. - wherein    According to Hest law, equation  (i) is sum of equation (ii) and (iii)   Option 1) x=y-z This option is incorrect  Option 2) z=x+y This option is incorrect  Option 3) x=y+z This option is...
Engineering
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When 5 litres of a gas mixture of methane and propane is perfectly combusted at 0o C and 1 atmosphere, 16 litre of oxygen at the same temperature and pressure is consumed. The amount of heat released from this combustion in kJ $(\Delta H_{comb}(CH_4))= 890 \:\:kJ\:\:mol^{-1}, \:\: \Delta H_{comb}(C_3H_8)=2220\: kJ\: mol^{-1})$ is

• Option 1)

32

• Option 2)

38

• Option 3)

317

• Option 4)

477

Enthalpy of combustion - Amount of Enthalpy change when 1 mole of substance is completly burn in excess of Oxygen - wherein         Total number of mole of   Total number of mole of    Heat liberated = 0.13*890+0.09*2220= 317 kJ Option 1) 32 Incorrect option Option 2) 38 Incorrect option Option 3) 317 Correct option Option 4) 477 Incorrect option
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