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C' = KC C' = 110pF , C = 50pF 110 = K x 50 K= 110/50 = 2.2  Thus, K = 2.2[no units]  for oil
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The components of the resultant force on it along & perpendicular to the string and the acceleration of one of the balls as follows:
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As we have learned Potential Difference - -       Option 1) Option 2) Option 3) Option 4)
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As we have learned Series Grouping - - wherein     Given network can be simplified as follows     Given that equivalent capacitance between A and B i.e., CAB But    hence       Option 1) Option 2) Option 3) Option 4)
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As we have learned Gauss's Law - Total flux linked with a closed surface called Gaussian surface. Formula:   - wherein No need to be a real physical surface. Qenc - charge enclosed by closed surface.     By using     Option 1) Option 2) Option 3) Option 4) None of the above
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As we hav learnt,   when Charged Particle at rest in uniform field - Kinetiv Energy - -    Kinetic energy   Option 1) Option 2) Option 3) Option 4)
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As we have learnt,   Neutral Point due to two unlike Point - - wherein Where, x = distance between Q1 and Q2 Let the electric field is zero at a point P distance d from the charge +Q so at P. Since d> a i.e. point P must lies on negative x-axis as shown at a distance x from origin hence Actually P lies on negative x-axis so . Option 1) Only  Option 2) Only  Option 3) Both  Option 4)
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