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Engineering
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The two lines $\dpi{100} x=ay+b,z=cy+d\;$ and $\dpi{100} x=a'y+b',z=c'y+d'\;$ are perpendicular to each other if

• Option 1)

$aa'+cc'=-1\;$

• Option 2)

$\; aa'+cc'=1\;$

• Option 3)

$\; \frac{a}{a'}+\frac{c}{c'}=-1\;$

• Option 4)

$\; \frac{a}{a'}+\frac{c}{c'}=1$

As we learnt in  Condition for perpendicularity - or -     Option 1) Incorrect Option   Option 2) Correct Option   Option 3) Incorrect Option   Option 4) Incorrect Option
Engineering
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The image of the point (–1, 3, 4) in the 3 plane $\dpi{100} x-2y=0$  is

• Option 1)

$\left ( -\frac{17}{3},-\frac{19}{3},4 \right )\;$

• Option 2)

$(15,11,4)$

• Option 3)

$\left ( -\frac{17}{3},-\frac{19}{3},1 \right )\; \;$

• Option 4)

$\left ( \frac{9}{5},-\frac{13}{5},4 \right )\; \;$

As we learnt in  Image of a point - Let be the image of point in the plane will be given by the formula  -    To find image we take Option 1) Incorrect Option   Option 2) Incorrect Option   Option 3) Incorrect Option   Option 4) Correct Option
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