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Eleven years earlier the average age of a family of 4 members was 28 years. Now the age of the same family with six members is yet the same, even when 2  children were born in this period. If they belong to the same parents and the age of the first child at the time of the birth of the younger child was same as there were total family members just after the birth of the youngest members of this family,  then  the present age of the youngest member of the family.

• Option 1)

3 years

• Option 2)

4 years

• Option 3)

6 years

• Option 4)

None of these

• Option 5)

5 years

The present age of the youngest member of the family is:

In a family of five persons A, B,  C, D and E each and everyone loves one another very much. Their birthdays are in different months and on different dates. A remembers that his birthday is between 25th and 30th, of B it is between 20th and 25th , of C it is between 10th and 20th , of D it is between 5th and 10th and of E it is between 1st to 5th of the month, the sum of the date of birth is defined as the addition of the date  and the month, for example 12th January will be written as 12/1 and will add to a sum of date of 13. (Between 25th and 30th includes both 25 and 30)

If the date of birth of four of them are prime numbers, then find the maximum  average of the sum of their dates of birth.

• Option 1)

27.2

• Option 2)

28.5

• Option 3)

28

• Option 4)

None of these

• Option 5)

26.1

The maximum average of the sum of their dates of birth is:

The average age of a couple is 25 years. The average age of the family just after the birth of the first child was 18 years. The average age of family just after the second  child was born was 15 years. The average age of the family after the third and the   fourth children (who are twins) were born was 12 years. If the present average age  of the family of six persons is 16 years, how old is the eldest child?

• Option 1)

5 years

• Option 2)

7 years

• Option 3)

8 years

• Option 4)

9 years

• Option 5)

6 years

Couple sum of ages = 50 years Couple + after child = 54 years Couple + 2 child = 60 years present age = 96 years H+W= 50 H+W+I = 54                  As just after birth of first child (I) = 0 H+W+I+II = 60 => 29+29+2+0 H+W+I+II+III+IV = 72 =>32+32+5+3+0+0 Present = 96,  so 24 years gap each will grow 4 years, I child = 5+4 = 9 years
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