A is 50% more than B, C is 2/3 of A and D is 60% more than C. Now, each of A,B,C and D is increased by 10%. Find what per cent of B is D (after the increase)
150%
160%
175%
176%
$\begin{aligned} & \text { Let } B=100 \quad A=150 \quad C=2 A / 3=100 \\ & D=60 \% \text { of } 100+100=160 \\ & \text { New } A=(150 * 10 / 100)+150=165 \\ & \text { New } B=(100 * 10 / 100)+100=110 \\ & \text { New } C=(100 * 10 / 100)+100=110 \\ & \text { New } D=(160 * 10 / 100)+160=176 \\ & \% D \text { with respect to } B=(176 / 110) * 100=160 \% \\ & \text { Option B }\end{aligned}$