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A triangle having sides 10, 6, 8 units. Then the radius of the incircle is  

Option: 1

3 units


Option: 2

1 unit


Option: 3

4 units


Option: 4

2 units


Answers (1)

best_answer

Given that sides of the triangle as 6, 8, 10

This is Pythagoras triplet, so the triangle is the right-angle triangle. with hypotenuse 10

semiperimeter, (s) = 1/2 (6 + 8 + 10) = 12

Area of triangle ABC = 1/2 (6\times8) =24

So, if the inradius of ABC is r

\\\mathrm{Area \;of\;\Delta ABC=r\times s}\\\\\mathrm{r=\frac{Area \;of\;\Delta ABC}{s}}

In radius = 24/12 = 2 units

 

Posted by

manish painkra

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