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In the March 2022 Russian-Ukraine confrontation, a large number of Russian GRU field intelligence operatives were operating in Ukraine territory. 

But after a few months, made suspicious by a few not so normal intelligence leaks at the field level, the head of GRU, Admiral Igor Kostyukov, got suspicious. He decided to form a committee of four members out of the eight elite and loyal Spetsnaz commandos of the rank of Colonel in the GRU – A to H. Out of them, apart from being ruthless operatives, Colonel B and Colonel C had an excellent cover for themselves, being the star players in the Russian men’s ice-hockey team which in February 2022 won silver at the Winter Olympics in Beijing. The Admiral wanted the committee members to infiltrate the Ukrainian intelligence network as upper class family-men, and hence made it clear that the committee so formed should have two male and two female Spetsnaz Colonels.

He appointed his five GRU Directorate Heads to suggest their choice for the members of the committee out of the eight Colonels. 

The report of suggestions placed at Admiral Kostyokov’s table within a day was as follows :

GRU Directorate 1 Head

B

C

G

H

GRU Directorate 2 Head

A

D

E

H

GRU Directorate 3 Head

C

E

F

G

GRU Directorate 4 Head

B

D

E

G

GRU Directorate 5 Head

A

F

G

H

It was also noted that in all the suggestions made above there was exactly one married couple present, except the suggestions of the GRU Directorate 5 Head, where there was none.

Question:

Which of the following must be a married couple 

Option: 1

D and H

 

 


Option: 2

B and G


Option: 3

C and E

 


Option: 4

None of the above


Answers (1)

best_answer

Let us first determine the genders and the couples of the Spetsnaz Colonels :

We know B and C are male, as they are players in the men’s ice hockey team of Russia. Hence G and H must be female as per Dir 1 Head’s suggestion, as there are two men and two women in each suggestion of the committee. Hence: 

GRU Directorate 1 Head

B

C

G

H

GRU Directorate 2 Head

A

D

E

H

GRU Directorate 3 Head

C

E

F

G

GRU Directorate 4 Head

B

D

E

G

GRU Directorate 5 Head

A

F

G

H

Now, A and F must be male as per Dir 5 Head’s suggestion. Hence E must be a female as per Dir 3 Head’s suggestion. Hence we can conclude D must be a male as per Dir 4 Head’s suggestion. Finally as per Dir 2 Head’s suggestion, A must be a male too. Hence:

GRU Directorate 1 Head

B

C

G

H

GRU Directorate 2 Head

A

D

E

H

GRU Directorate 3 Head

C

E

F

G

GRU Directorate 4 Head

B

D

E

G

GRU Directorate 5 Head

A

F

G

H

Now from the Dir 1 Head’s suggestion, let us assume that B and G are married, and hence is the couple. From this assumption, the following four cases of probable couples in each suggestion can be concluded:

GRU Directorate 1 Head

B

C

G

H

 

BG

BG

BG

BG

GRU Directorate 2 Head

A

D

E

H

 

AH

DH

AH

DH

GRU Directorate 3 Head

C

E

F

G

 

CE

CE

FE

FE

GRU Directorate 4 Head

B

D

E

G

 

BG

BG

BG

BG

GRU Directorate 5 Head

A

F

G

H

 

AH

 

AH

 

But AH cannot be a couple as there is no couple in the suggestion of Dir 5 Head. Hence only 2nd and 4th cases are possible. Hence:

           

No

Yes 

No

Yes 

GRU Directorate 1 Head

B

C

G

H

 

BG

BG

BG

BG

GRU Directorate 2 Head

A

D

E

H

 

AH

DH

AH

DH

GRU Directorate 3 Head

C

E

F

G

 

CE

CE

FE

FE

GRU Directorate 4 Head

B

D

E

G

 

BG

BG

BG

BG

GRU Directorate 5 Head

A

F

G

H

 

AH

 

AH

 

Likewise, let us assume that B and H are married, and hence is the couple. From this assumption, the following four cases of probable couples in each suggestion can be concluded:

GRU Directorate 1 Head

B

C

G

H

 

BH

BH

BH

BH

GRU Directorate 2 Head

A

D

E

H

 

AE

AE

DE

AE

GRU Directorate 3 Head

C

E

F

G

 

FG

 

FG

FG

GRU Directorate 4 Head

B

D

E

G

 

DG

DG

DE

 

GRU Directorate 5 Head

A

F

G

H

 

FG

 

FG

FG

But FG cannot be a couple in the suggestion of Dir 5 Head, and all other four suggestions must have a couple. So no case is possible. Hence:

           

No

No

No

No

GRU Directorate 1 Head

B

C

G

H

 

BH

BH

BH

BH

GRU Directorate 2 Head

A

D

E

H

 

AE

AE

DE

AE

GRU Directorate 3 Head

C

E

F

G

 

FG

 

FG

FG

GRU Directorate 4 Head

B

D

E

G

 

DG

DG

DE

 

GRU Directorate 5 Head

A

F

G

H

 

FG

 

FG

FG

Now from the Dir 1 Head’s suggestion, let us assume that C and G are married, and hence are the couple. From this assumption, the following three cases of probable couples in each suggestion can be concluded:

GRU Directorate 1 Head

B

C

G

H

 

CG

CG

CG

GRU Directorate 2 Head

A

D

E

H

 

AH

DH

DE

GRU Directorate 3 Head

C

E

F

G

 

CG

CG

CG

GRU Directorate 4 Head

B

D

E

G

 

BE

BE

DE

GRU Directorate 5 Head

A

F

G

H

 

AH

 

 

But AH cannot be a couple as there is no couple in the suggestion of Dir 5 Head. Hence only 2nd and 3rd cases are possible. Hence:

           

No

Yes

Yes

GRU Directorate 1 Head

B

C

G

H

 

CG

CG

CG

GRU Directorate 2 Head

A

D

E

H

 

AH

DH

DE

GRU Directorate 3 Head

C

E

F

G

 

CG

CG

CG

GRU Directorate 4 Head

B

D

E

G

 

BE

BE

DE

GRU Directorate 5 Head

A

F

G

H

 

AH

 

 

Likewise, let us assume that C and H are married, and hence is the couple. From this assumption, the following two cases of probable couples in each suggestion can be concluded:

GRU Directorate 1 Head

B

C

G

H

 

CH

CH

GRU Directorate 2 Head

A

D

E

H

 

AE

DE

GRU Directorate 3 Head

C

E

F

G

 

FG

FG

GRU Directorate 4 Head

B

D

E

G

 

DG

DE

GRU Directorate 5 Head

A

F

G

H

 

FG

FG

But FG cannot be a couple in the suggestion of Dir 5 Head, and all other four suggestions must have a couple. So no case is possible. Hence:

           

No

No

GRU Directorate 1 Head

B

C

G

H

 

CH

CH

GRU Directorate 2 Head

A

D

E

H

 

AE

DE

GRU Directorate 3 Head

C

E

F

G

 

FG

FG

GRU Directorate 4 Head

B

D

E

G

 

DG

DE

GRU Directorate 5 Head

A

F

G

H

 

FG

FG

As observed above, only the second and fourth sub-case of the case where B and G are married or the second and third sub-case of the case where C and G are married will hold.

By observation, we can say that there is no couple who is mandatory in all the different cases possible.

Hence the answer is ‘None of the above’

Posted by

vinayak

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