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Equation of tangent to the circle x^{2}+y^{2}-4x-16=0 at point (0,4) is

Option: 1

2x-y+16=0


Option: 2

2x+4y+16=0


Option: 3

2x-4y-16=0


Option: 4

2x-4y+16=0


Answers (1)

Equation of tangent to the circle x^{2}+y^{2}-4x-16=0 at point (0,4) is

4y-2(x+0)-16=0

2x-4y+16=0

Posted by

Ramraj Saini

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