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Equation of tangent to the circle x^2+y^2+4x+4y+16=0 at point (x_1,y_1) is

Option: 1

xx_1+yy_1+2(x+x_1)+2(y+y_1)+8=0


Option: 2

xx_1+yy_1+4(x+x_1)+4(y+y_1)+16=0


Option: 3

xx_1+yy_1+2(x+x_1)+2(y+y_1)+16=0


Option: 4

None of these


Answers (1)

best_answer

Equation of tangent to the circle x^2+y^2+4x+4y+16=0 at point (x_1,y_1) is

\\xx_1+yy_1+2(x+x_1)+2(y+y_1)+16=0\\

Posted by

Sanket Gandhi

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