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Factors of $\left[x^{2}+\frac{x}{6}-\frac{1}{6}\right]$ are:
Option: 1
$\frac{1}{6}(2 x-1)(3 x+1)$

Option: 2
$\frac{1}{6}(2 x-1)(3 x-1)$

Option: 3
$\frac{1}{6}(2 x+1)(3 x-1)$

Option: 4
$\frac{1}{6}(2 x+1)(3 x+1)$

Answers (1)

best_answer

$\left[x^{2}+\frac{x}{6}-\frac{1}{6}\right]$

$=\frac16\left[6x^{2}+x-1\right]$

$=\frac16\left[6x^{2}+3x-2x-1\right]$

$=\frac16(3x-1)(2x+1)$

Posted by

Gautam harsolia

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