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If ABCD and ABPQ are two parallelograms and M is a point on AQ and BMP is a triangle.

\text { Then, } \operatorname{ar}(\Delta B M P)=\frac{1}{2} \operatorname{ar}(\| g \operatorname{m} A B C D) \text { is }

Option: 1

True


Option: 2

False


Answers (1)

best_answer

\operatorname{ar}(\triangle B M P)=\frac{1}{2} \operatorname{ar}(\| g \operatorname{m} A B P Q)=\frac{1}{2} \operatorname{ar}(\| g m A B C D)

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chirag

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