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If the line y = mx-2 is tangent to the circle $x^2+y^2=4$ , then
Option: 1
m = 1

Option: 2
m = -2

Option: 3
m = 2

Option: 4
m = 0

Answers (1)

best_answer

Given equation of the circle is $x^2+y^2=4$

a = 2

Equation of line , y = mx -2

Since the line is tangent to the circle, so

$\\2=\frac{|-2|}{\sqrt{1+m^2}}\\\Rightarrow m=0$

Posted by

HARSH KANKARIA

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