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if $\log_ba=\left ( \frac{\log_cb}{\log_ca} \right )^k$ , then value of k is
Option: 1
0

Option: 2
1

Option: 3
-1

Option: 4
None of these

Answers (1)

$\log_ba=\left ( \frac{\log_cb}{\log_ca} \right )^k$

$\frac{\log_cb}{\log_ca}=\log_ab$

$\\\log_ba=\left (\log_ab \right )^k\\\log_ba=\frac{1}{\log_ab}\\k=-1$

Posted by

Ramraj Saini

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