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If \alpha and \beta are the zeroes of x^{2}+6 x+8 then the value of (\alpha+\beta) is ?

Option: 1

6


Option: 2

-6


Option: 3

5


Option: 4

-5


Answers (1)

best_answer

\\\text {sum of zeroes }=\alpha+\beta=-\frac{b}{a}=\frac{-(\text { Coefficient of } x)}{\text { Coefficient of } x^{2}} \\\\ \text{product of zeroes} =\alpha \beta=\frac{c}{a}=\frac{\text { Constant term }}{\text { Coefficient of } x^{2}}

Sum of roots = -6/1 = -6

 

 

Posted by

Irshad Anwar

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