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If x = log2 8 and y = log4 8, then \frac{1}{x}+\frac{1}{y}=

Option: 1

\frac{1}{4}


Option: 2

\frac{1}{4}


Option: 3

\frac{1}{2}


Option: 4

1


Answers (1)

best_answer

Given that

x = log2 8 and y = log4 8

\\\frac{1}{x}=\log_82\;\;and\;\;\frac{1}{y}=\log_84\\\\\frac{1}{x}+\frac{1}{y}=\log_82+\log_84\\\Rightarrow \log_8(2\times4)=\log_88=1

Posted by

Suraj Bhandari

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