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If x = log₂ 8 and y = log₄ 8, then $\frac{1}{x}+\frac{1}{y}=$
Option: 1
$\frac{1}{4}$

Option: 2
$\frac{1}{4}$

Option: 3
$\frac{1}{2}$

Option: 4
1

Answers (1)

best_answer

Given that

x = log₂ 8 and y = log₄ 8

$\\\frac{1}{x}=\log_82\;\;and\;\;\frac{1}{y}=\log_84\\\\\frac{1}{x}+\frac{1}{y}=\log_82+\log_84\\\Rightarrow \log_8(2\times4)=\log_88=1$

Posted by

Suraj Bhandari

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