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In ABC, AD is median. If $AB^2+AC^2=100\;cm^2$ and CD = 5 cm, then AD is (in cm)

Option: 1
5 cm

Option: 2
10 cm

Option: 3
7 cm

Option: 4
None of these

Answers (1)

best_answer

Given that $AB^2+AC^2=100\;cm^2$ and CD = 5 cm

Using the concept of Appolonius Theorem

$A B^{2}+A C^{2}=2\left(A D^{2}+D C^{2}\right)$

$\\100=2(AD^2+25)\\AD=5$

AD = 5cm

Posted by

Divya Prakash Singh

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