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In isosceles triangle $ABC$ , $\angle A=\angle B$ then $\angle A\leq90^o$
Option: 1
True

Option: 2
False

Answers (1)

If $\angle A= 90^o$

then $\angle A=\angle B= 90^o$

So

$\angle A+\angle B+\angle C= 180^o$

$180^0+\angle C= 180^o$

$\angle C= 0^o$

But in a triangle a angle can't be zero

Hence,

this statement is false

Posted by

Ramraj Saini

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