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In the adjoining figure, O is the centre of a circle. If ∠ ACB = 50° and C is a point on the circle then ∠ AOB =

Option: 1

50°


Option: 2

100°


Option: 3

150°


Option: 4

90°


Answers (1)

From the theorem

\\\angle \mathrm{ACB}=\frac{1}{2} \angle \mathrm{AOB} \\2\times \angle \mathrm{ACB}=\angle \mathrm{AOB} \\ \\ {2} \times 50^{\circ}=100^{\circ}

Posted by

Sumit Saini

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