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  • In the adjoining figure, O is the centre of a circle. If ∠ OEB = 30° and C is a point on the circle then ∠ ACB = <img alt="" src="https://cdn.entrance360.c

In the adjoining figure, O is the centre of a circle. If ∠ OEB = 30° and C is a point on the circle then ∠ ACB =

Option: 1

120°


Option: 2

50°


Option: 3

30°


Option: 4

60°


Answers (1)

best_answer

Since, OA  = OB

So, ∠ OBA = ∠ OAB =  30°

Therefore, ∠ AOB =  180° - (30° + 30°) = 120° 

and from the theorem

\angle \mathrm{ACB}=\frac{1}{2} \angle \mathrm{AOB}=\frac{1}{2} \times 120^{\circ}=60^{\circ}

Posted by

Divya Prakash Singh

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