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In the adjoining figure, the value of y is (AOB is straight line)

Option: 1
$\large 40^0$

Option: 2
$\large 50^0$

Option: 3
$\large 60^0$

Option: 4
$\large 70^0$

Answers (1)

best_answer

$\large x^0+90^0+ y^0=180^0\Rightarrow x^0+y^0=90^0$

and

$\large 3x^0+60^0=180^0\Rightarrow x^0=40^0$

from above we get

$\large y^0=50^0$

Posted by

Gaurav

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