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In the adjoining figur, O is the centre of a circle, PO bisects angle APC and AB , CD are chord of circle, then AB = CD. (True/False)

Option: 1

True


Option: 2

False


Answers (1)

best_answer

Draw OE perpendicular to AB and OF perpendicular to CD

Consider triangle OEP and OFP

∠ OEP = ∠ OFP  =90°

OP =OP (common)

∠ OPE = ∠ OPF  (Given)

? OEP ≅ ? OFP

This gives OE = OF

chords AB and CD are equidistant from the centre O

So, AB = CD

Posted by

HARSH KANKARIA

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