In the adjoining figur, O is the centre of a circle, PO bisects angle APC and AB , CD are chord of circle, then AB = CD. (True/False)
True
False
Draw OE perpendicular to AB and OF perpendicular to CD
Consider triangle OEP and OFP
∠ OEP = ∠ OFP =90°
OP =OP (common)
∠ OPE = ∠ OPF (Given)
? OEP ≅ ? OFP
This gives OE = OF
chords AB and CD are equidistant from the centre O
So, AB = CD