In the figure, ABCD is a cyclic quadrilateral, AB || CD and if ∠ BAD = 110°, then ∠ ABC =
110°
100°
70°
55°
BA || DC and DA is the transversal.
So, ∠ BAD + ∠ ADC = 180° (sum of interior opposite angle)
110° + ∠ ADC = 180°
∠ ADC = 70°
We know that the opposite angles of a cyclic quadrilateral are supplementary
∠ ADC + ∠ ABC = 180°,
then ∠ ABC = 180° - 70° = 110°