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Length of a tangent from a point (4,-6) to the circle x^{2}+y^{2}+2x-16=0 is

Option: 1

3\sqrt{5}


Option: 2

2\sqrt{10}


Option: 3

7


Option: 4

2\sqrt{11}


Answers (1)

Length of tangent = \sqrt{\left(4\right)^2+\left(-6\right)^2+2\left(4\right)-16}=\sqrt{44}=2\sqrt{11}

Posted by

Kshitij

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