Get Answers to all your Questions

header-bg qa

The equatiomn of the circle whose centre is at (2,2) and having radius 2 unit is

Option: 1

x^2+y^2-4x+4y+4=0


Option: 2

x^2+y^2+4x+4y+4=0


Option: 3

x^2+y^2-4x+4y+4=0


Option: 4

x^2+y^2-4x-4y+4=0


Answers (1)

best_answer

Given centre of the circle (h,k) = (2,2)

and radius = 2

equation of circle 

\\\Rightarrow (x-2)^2+(y-2)^2=2^2\\\Rightarrow x^2-4x+4+y^2-4y+4=4\\\Rightarrow x^2+y^2-4x-4y+4=0

Posted by

vinayak

View full answer