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The equation of the tangent to the circle x^{2}+y^{2}-2x+2y-16=0 at point (-4,0) is

Option: 1

x+y=6


Option: 2

x-y=6


Option: 3

x+y+6=0


Option: 4

None of these


Answers (1)

best_answer

Equation of circle x^{2}+y^{2}-2x+2y-16=0

so g = -1, f = 1 and c = -16

given point (4,2)

eq of tangent

4x+2y-\left(x+4\right)+\left(y+2\right)-16=0

x+y=6

Posted by

Ritika Harsh

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