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The height of an equilateral triangle having each side 6 cm, is

Option: 1

3\sqrt{2}


Option: 2

2\sqrt{3}


Option: 3

2\sqrt{2}


Option: 4

3\sqrt{3}


Answers (1)

AB = BC = AC = 6cm

ABC is an equilateral triangle therfore AD\perpBC and BD = DC = 3cm

\\\therefore AD=\sqrt{AC^2-CD^2}=\sqrt{6^2-3^2}=\sqrt{27}=3\sqrt3

Posted by

Ramraj Saini

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