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The population of a town is 12000, if the number of males be increased by 6% and that of females by 8%, the population would be increased to 12800. Find the strength of females in the town.

Option: 1

3500


Option: 2

4000


Option: 3

4500


Option: 4

5000


Answers (1)

best_answer

Let population of male be x and female y respectively

$\mathrm{x}+\mathrm{y}=12000 \ldots \ldots \ldots \ldots \ldots$

Now, acc. To question

$(106 x / 100)+(108 y / 100)=12800 \ldots \ldots \ldots \ldots \ldots b$

Solving a and b we get

Y=4000

 

Posted by

Gaurav

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