The population of a town is 12000, if the number of males be increased by 6% and that of females by 8%, the population would be increased to 12800. Find the strength of females in the town.
3500
4000
4500
5000
Let population of male be x and female y respectively
$\mathrm{x}+\mathrm{y}=12000 \ldots \ldots \ldots \ldots \ldots$
Now, acc. To question
$(106 x / 100)+(108 y / 100)=12800 \ldots \ldots \ldots \ldots \ldots b$
Solving a and b we get
Y=4000