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The range of $y^{2}=-x^{2}+3x-2$ is
Option: 1
$\left ( -\infty,\frac{1}{4} \right ]$

Option: 2
$\left ( -\infty,\infty \right )$

Option: 3
$\left [ \frac{1}{4},\infty \right )$

Option: 4
None of these

Answers (1)

best_answer

$a=-1\\$ , so range is $\left ( -\infty,\frac{-D}{4a} \right ]\\$

$a=-1,b=3,c=-2\\$

$D=b^{2}-4ac=9-4\left ( -1 \right )\left ( -2 \right )=1\\$

$\frac{-D}{4a}=\frac{-1}{4\cdot \left ( -1 \right )}=\frac{1}{4}\\$

Range $:\left ( -\infty,\frac{1}{4} \right ]$

Posted by

Anam Khan

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