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Which of following is not a solution for x - 2y = 4.

Option: 1

(0,-2)


Option: 2

(4 \sqrt{2}, \sqrt{2})


Option: 3

(6,1)


Option: 4

(4,0)


Answers (1)

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The given equation may be written as x - 2y - 4 = 0

(i) Putting x=0 and y=-2

LHS =\{0-2 \times(-2)-4\}=\{0+4-4\}=0= RHS \\ \therefore \quad(0,-2) $ is a solution of x-2 y=4

(ii) Putting x=4 \sqrt{2} and y=\sqrt{2}, we get

\begin{aligned} LHS &=(4 \sqrt{2}-2 \times \sqrt{2}-4)=(4 \sqrt{2}-2 \sqrt{2}-4) \\ &=(2 \sqrt{2}-4) \neq 0= RHS \end{aligned} \\\therefore \quad(4 \sqrt{2}, \sqrt{2})$ is not a solution of x-2 y=4

(iii) Putting x=6 and y=1, we get

LHS =(6-2 \times 1-4)=(6-2-4)= 0= RHS \\ \therefore \quad(2,0) $ is not a solution of x-2 y=4

(iv) Putting x=4 and y=0 we get

LHS =(4-2 \times 0-4)=(4-0-4)=0= RHS \\\therefore \quad(4,0)$ is a solution of x-2 y=4

Posted by

Ajit Kumar Dubey

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