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Which of the following point lies inside the circle x^{2}+y^{2}-2y-10=0

Option: 1

(1,2)


Option: 2

(2,-2)


Option: 3

(4,2)


Option: 4

both (b) and (c)


Answers (1)

Equation of circle x^{2}+y^{2}-2y-10=0

(a) (1,2)

\left(1\right)^2+\left(2\right)^2-2\left(2\right)-10=-9<0

point lies inside

(b) (2,-2)

\left(2\right)^2+\left(-2\right)^2-2\left(-2\right)-10=2>0

point lies outside

(c) (4,2)

\left(4\right)^2+\left(2\right)^2-2\left(2\right)-10=6>0

point lies outside

Posted by

Sumit Saini

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