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Which of the following point lies outside the circle x^{2}+y^{2}-4x+2y-10=0

Option: 1

(2,6)


Option: 2

(2,-3)


Option: 3

(4,6)


Option: 4

Both (a) and (c)


Answers (1)

best_answer

Equation of circle x^{2}+y^{2}-4x+2y-10=0

(a) (2,6)

\left(2\right)^2+\left(6\right)^2-4\left(2\right)+2\left(6\right)-10=34>0

point lies outside

(b) (2,-3)

\left(2\right)^2+\left(-3\right)^2-4\left(2\right)+2\left(-3\right)-10=-11<0

point lies inside

(c) (4,6)

\left(4\right)^2+\left(6\right)^2-4\left(4\right)+2\left(6\right)-10=38>0

point lies outside

Posted by

Ritika Jonwal

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