Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • 0.5 F of electricity is passed through 500 mL of copper sulphate solution. The amount of copper (in g) which can be deposited will be:Option: 1

0.5 F of electricity is passed through 500 mL of copper sulphate solution. The amount of copper (in g) which can be deposited will be:

Option: 1

31.75


Option: 2

15.8


Option: 3

47.4


Option: 4

63.5


Answers (1)

best_answer

\mathrm{Cu}^{2+}+2 e^{-} \longrightarrow \mathrm{Cu}

\begin{array}{l}{2 \mathrm{\: F}=1 \mathrm{\: mol} \text { of } \mathrm{Cu}=63.5 \mathrm{\: g\: of} \mathrm{\: Cu}} \\\\ {0.5 \mathrm{\: F}=\frac{63.5}{2} \times 0.5=15.8 \mathrm{g}}\end{array}

Posted by

Anam Khan

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

UP NEET AYUSH 2025: Registration for stray vacancy round 2 ends in two days
anam-khan

Uttarakhand plans 5-year mandatory service for all MBBS doctors before PG; Rs 1 crore penalty in place
anam-khan

Uttarakhand NEET AYUSH 2025: Registration begins for mop-up round counselling; who is eligible?

Latest Question