Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa

3. The binding energy of \mathrm{f}_{17} \mathrm{Cl}^{35} nucleus is 298 MeV. Find its atomic mass(approximately). The mass of hydrogen atom\left({ }_1 \mathrm{H}^1\right) is 1.008143 a.m.u. and that of a neutron is 1.008986 a.m.u. Given 1 a.m.u. = 931 MeV.

Option: 1

35 amu


Option: 2

34 amu


Option: 3

32 amu


Option: 4

36 amu


Answers (1)

best_answer

The { }_{17} \mathrm{Cl}^{35} atom has 17 protons and 18 neutrons in its nucleus.

Mass of 17 \mathrm{{ }_1 \mathrm{H}^1} atom has 17 protons and 18
neutrons in its nucleus.
\mathrm{Mass \ of \17 \ protons =17 \times 1.008143 \mathrm{amu}= 17.138431 amu.}

Mass of 18 neutrons = 18 \times1.008986= 18.161748 a.m.u.
Total = 35.300179 a.m.u.
\mathrm{\text { Mass defect } \Delta \mathrm{m}=298 / 931=0.320085 \text { a.m.u. }}
The atomic mass of { }_{17} \mathrm{Cl}^{35} would be the sum of
equivalent of the binding energy of the nucleus.
Hence atomic mass of 

\mathrm{\begin{aligned} & { }_{17} \mathrm{Cl}^{35}=35.300179-0.320085 \\ & =34.980094 \text { a.m.u. } \end{aligned}}

Posted by

Gunjita

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

CBI arrests Latur coaching centre founder in NEET-UG paper leak case; exam questions found on phone
anam-khan

NEET UG ‘Paper Leak’: CBI conducts searches at Renukai Chemistry Classes in Latur
anam-khan

Abolish NEET, restore state CET; Karnataka urges Centre after paper leak row

Latest Question