6 g of ethane (C2H6) is burnt in excess of O2. The moles of H2O formed would be
0.2
0.4
0.6
0.8
The reaction occurs as follows:
Molar Mass of Ethane = 30 g/mole.
Molar mass of water = 18 g/mole.
From the Equation,
? 2 x 30 grams of Ethane produces 6 x 18 grams of Water.
∴ 1 gram of the Ethane produces (9/5) grams of Water.
∴ 6 grams of Ethane produces 10.8 grams of Water.
Now, Using the Formula,
No. of Moles of Water = Mass/Molar Mass
= 10.8/18
= 0.6 moles.
Therefore, Option(3) is correct.