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6 g of ethane (C2H6) is burnt in excess of O2. The moles of H2O formed would be

Option: 1

0.2


Option: 2

0.4


Option: 3

0.6


Option: 4

0.8


Answers (1)

best_answer

The reaction occurs as follows:

2 \mathrm{C}_{2} \mathrm{H}_{6}+7 \mathrm{O}_{2}\: \rightarrow \: 4 \mathrm{CO}_{2}+6 \mathrm{H}_{2} \mathrm{O}

Molar Mass of Ethane = 30 g/mole.
Molar mass of water = 18 g/mole.

From the Equation,

? 2 x 30 grams of Ethane produces 6 x 18 grams of Water.
∴ 1 gram of the Ethane produces (9/5) grams of Water.
∴ 6 grams of Ethane produces 10.8 grams of Water.


Now, Using the Formula,
 No. of Moles of Water = Mass/Molar Mass
 = 10.8/18
 = 0.6 moles.

Therefore, Option(3) is correct.

Posted by

rishi.raj

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