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  • A and B are two metals with threshold frequencies <img alt="1.8 \times 10^{14} \mathrm{~Hz}" src="https://entrancecorner.oncodecogs.com/gif.latex?1.8%20%5Ctimes%2010%5E%7B14%7D%20%5Cmathrm%7B%7EHz%

A and B are two metals with threshold frequencies 1.8 \times 10^{14} \mathrm{~Hz}  and 2.2 \times 10^{14} \mathrm{~Hz}. Two identical photons of energy 0.825 \mathrm{e}\nu each are incident on them. Then photoelectrons are emitted in (Take \mathrm{h}= 6.6 \times 10^{-34} \mathrm{Js})
 

Option: 1

 B alone
 


Option: 2

 A alone
 


Option: 3

neither A nor B
 


Option: 4

both A and B.


Answers (1)

Photoelectrons are emitted in A alone. Energy of electron needed if emitted from \mathrm{A}=\frac{\mathrm{h}\nu}{\mathrm{e}} \mathrm{e}\nu

\begin{aligned} & \therefore \quad\mathrm {E_A}=\frac{\left(6.6 \times 10^{-34}\right) \times\left(1.8 \times 10^{14}\right)}{1.6 \times 10^{-19}}=0.74 \mathrm{e}\nu \\ & \mathrm{E_B}=\frac{\left(6.6 \times 10^{-34}\right) \times\left(2.2 \times 10^{14}\right)}{1.6 \times 10^{-19}}=0.91 \mathrm{e}\nu \end{aligned}

Incident energy 0.825 \mathrm{e} \nu is greater than 

\mathrm{E}_{\mathrm{A}}(0.74 \mathrm{e}\nu) \text{ but less than }\mathrm{E}_{\mathrm{B}}(0.91 \mathrm{e}\nu).

Posted by

Ramraj Saini

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