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  • A ball of mass 0.5 kg is dropped from a height of 40 m .

Q.31) A ball of mass 0.5 kg is dropped from a height of 40 m . The ball hits the ground and rises to a height of 10 m . The impulse imparted to the ball during its collision with the ground is (Take $\mathrm{g}=9.8 \mathrm{~m} / \mathrm{s}^2 \mathrm{~F}=$

A) 84 NS
 

B) 21 NS
 

C) 7 NS
 

D)  0

 

Answers (1)

best_answer


Speed just before impact: $v_1=\sqrt{2 \cdot 9.8 \cdot 40}=28 \mathrm{~m} / \mathrm{s}$
Speed just after rebound: $v_2=\sqrt{2 \cdot 9.8 \cdot 10}=14 \mathrm{~m} / \mathrm{s}$
Impulse $=$ change in momentum $=0.5 \cdot(14-(-28))=0.5 \cdot 42=21 \mathrm{Ns}$
Answer: (2) 21 NS

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Saumya Singh

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