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  • A beam of electrons is moving with constant velocity in a region having simultaneous perpendicular electric and magnetic fields of strength <img alt="20 \mathrm{Vm}^{-1}$ and $0.5 \mathrm{~T}" src=

A beam of electrons is moving with constant velocity in a region having simultaneous perpendicular electric and magnetic fields of strength 20 \mathrm{Vm}^{-1}$ and $0.5 \mathrm{~T} respectively at right angles to the direction of motion of the electrons. Then the velocity of electrons must be.

Option: 1

8 m/s


Option: 2

20 m/s


Option: 3

40 m/s


Option: 4

\frac{1}{40} \mathrm{~m} / \mathrm{s}


Answers (1)

best_answer

The electron moves with constant velocity without deflection. Hence, force due to magnetic field is equal and opposite to force due to electric field. \mathrm{q v B=q E \Rightarrow v=\frac{\mathrm{E}}{\mathrm{B}}=\frac{20}{0.5}=40 \mathrm{~m} / \mathrm{s}}

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Gautam harsolia

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