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  • A body A starts from rest with an acceleration . After 2 seconds, another body B starts from rest with a

A body A starts from rest with an acceleration a_{1}. After 2 seconds, another body B starts from rest with an acceleration a_{2} . If they travel equal distances in the 5th second, after the start of  A, then the ratio a_{1}:a_{2} is equal to

Option: 1

5:9


Option: 2

5:7


Option: 3

9:5

 


Option: 4

9:7


Answers (1)

best_answer

Time taken by the body A, 

{{t}_{1}}=5s

Acceleration of the body A ={{a}_{1}}

Time taken by the body B, {{t}_{2}}=5-2=3s

Acceleration of the body ={{a}_{2}}

Initial speed u=0
Distance covered in nth second after starting from rest S=\frac{a}{2}(2 n-1)

Distance covered by the first body in the fifth second after its start,

\mathrm{S}_{\mathrm{A}}=\frac{\mathrm{a}_1}{2}(2 \times 5-1)=\frac{9}{2} \mathrm{a}_1

Distance covered by the first body in the 3rd second after its start,

\begin{aligned} & S_B=u+\frac{a_2}{2}\left(2 t_2-1\right) \\ & S_B=0+\frac{a_2}{2}(2 \times 3-1)=\frac{5 a_2}{2} \end{aligned}

Since, {{S}_{A}}={{S}_{B}

\therefore \frac{9}{2}{{a}_{1}}=\frac{5}{2}{{a}_{2}}

{{a}_{1}}:{{a}_{2}}=5:9

Posted by

Deependra Verma

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