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  • A Capacitor of capacitance'C' is connected across an ac source of voltage V.given by .The dispalceme

A Capacitor of capacitance'C' is connected across an ac source of voltage V.given by V=V_{o}\sin \omega t.The dispalcement current between the plates of  the capacitor ,would then given by:

Option: 1

I_{d}=V_{0}\omega C\cos \omega t


Option: 2

I_{d}=\frac{V_{0}}{\omega C}\cos \omega t


Option: 3

I_{d}=\frac{V_{0}}{\omega C}\sin \omega t


Option: 4

I_{d}=V_{0}\omega C\sin \omega t


Answers (1)

best_answer

V=V_{o}\sin \omega t

Displacement current is in magnitude equal to conduction current

I_{d}=I_{c}=\frac{V}{x_{c}}=\frac{V_{0} \sin \omega_{t}}{\left(1/_{\omega c}\right)}

I_{d}=v_{0} \omega_{C}(\sin \omega t)

Posted by

vishal kumar

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