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A cell of e.m.f volt with no internal resistance is connected to a wire whose cross section changes. The wire has three sections of equal length. The middle section has a radius , whereas the radius of the outer two sections is 2. The ratio of the potential difference across section to the potential difference across section is

Option: 1

5


Option: 2

4


Option: 3

\frac{1}{2}


Option: 4

\frac{1}{4}


Answers (1)

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In series combination, I is constant, therefore \mathrm{V \propto R}

\mathrm{\frac{V_{A B}}{V_{C A}}=\frac{R_{A B}}{R_{C A}}=\frac{\rho \frac{I}{\pi a^2}}{\rho \frac{l}{\pi(2 a)^2}} \Rightarrow \frac{V_{A B}}{V_{C A}}=\frac{4}{1} }

Posted by

Kuldeep Maurya

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