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  • A circular ring of diameter 20 cm has a resistance of 0.01 . How much charge will flow through the ring if it is t

A circular ring of diameter 20 cm has a resistance of 0.01 \Omega. How much charge will flow through the ring if it is turned from a position perpendicular to a uniform magnetic field of 2.0 T to a position parallel to the field?

Option: 1

\mathrm{\pi C}


Option: 2

\mathrm{2\pi C}


Option: 3

\mathrm{3\pi C}


Option: 4

\mathrm{4\pi C}


Answers (1)

best_answer

Induced current flow \mathrm{=\mathbf{i}=\frac{\mathrm{d} \phi}{\mathrm{dt}} / \mathrm{R}}

The charge flow

 \mathrm{\begin{aligned} & =\mathrm{q}=\int_0^{\mathrm{t}} \mathrm{idt}=\frac{\int_{+1}^{+2} \mathrm{~d} \phi}{\mathrm{R}}=\frac{\left|\phi_2-\phi_1\right|}{\mathrm{R}} \\ & =\frac{|B \cdot A-0|}{R}=\frac{2 \pi(0.1)^2}{0.01} \\ & =2 \pi=6.28 \text { Coulombs } \end{aligned}}

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Pankaj

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