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A closely wound solenoid of 2000 turns and area of cross-section 1.5 x 10-4 mcarries a current of 2.0 A. It is suspended through its centre and perpendicular to its length, allowing it to turn in a horizontal plane in a uniform magnetic field 5 x 10-2 tesla making an angle of 30° with the axis of the solenoid. The torque on the solenoid will be

Option: 1

3 x 10-3 Nm


Option: 2

1.5 x 10-3 Nm


Option: 3

1.5 x 10-2 Nm


Option: 4

3 x 10-2 Nm


Answers (1)

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\begin{array}{l} M=N i A=2000 \times 2 \times 1.5 \times 10^{-4}=0.6 A-m^{2} \\ \tau=M B \sin 30^{\circ} =0.6 \times 5 \times 10^{-2} \times \frac{1}{2}=1.5 \times 10^{-2} N-m \end{array}

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