Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • A conducting bar pulled with a constant speed v on a smooth conducting rail. The region has a steady magnetic field of induction B as shown in the figure. If the speed of the bar is doubled then th

A conducting bar pulled with a constant speed v on a smooth conducting rail. The region has a steady magnetic field of induction B as shown in the figure. If the speed of the bar is doubled then the rate of heat dissipation will

Option: 1

remain constant


Option: 2

become quarter of the initial value


Option: 3

become four fold


Option: 4

get doubled.


Answers (1)

best_answer

\mathrm{\text { The induced emf between } \mathrm{A} \text { and } \mathrm{B}=\mathrm{E}=\mathrm{B} \ell \mathrm{v}}

\mathrm{\Rightarrow \quad \text { The induced current }=\mathrm{i}=\frac{\mathrm{E}}{\mathrm{R}}}

\mathrm{\Rightarrow \quad \mathrm{i}=\frac{\mathrm{B} \ell \mathrm{v}}{\mathrm{R}}}

\mathrm{\text { The electrical power }=\mathrm{P}=\mathrm{i}^2 \mathrm{R}}

\mathrm{=\frac{\mathrm{B}^2 \ell^2 \mathrm{v}^2}{\mathrm{R}}}

Since v is doubled, the electrical power, becomes four times. Since heat dissipation per second is proportional to electrical power, it becomes four fold.

 

Posted by

avinash.dongre

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

NEET UG 2026 correction facility opens at neet.nta.nic.in; exam on May 3
anam-khan

NEET 2026 LIVE: NTA application correction window closes today; admit card, exam dates, pattern

Latest Question